Erdős problem 1192
Does there exist, for all , a basis of order (so that for all large ) such that for all ?
Sources
FormalConjectures/ErdosProblems/
1192.lean
Retained formal statement
Ruzsa [Ru90] proved that the answer is yes for .
∃ A, (∀ᶠ (n : ℕ) in Filter.atTop, Erdos1192.f_r A 2 n > 0) ∧ (fun x => ∑ n ∈ Finset.range (x + 1), ↑(Erdos1192.f_r A 2 n) ^ 2) =O[Filter.atTop] fun x => ↑xSolvedStatement only, no proof