Erdős problem 168
Sanity check: if S is a maximal non ternary subset of {1,..., N} then F N is given by the cardinality of S
Sources
FormalConjectures/ErdosProblems/
168.lean
Retained formal statement
Sanity check: elements of IntervalNonTernarySets N are precisely non ternary subsets of {1,...,N}
∀ (N : ℕ) (S : Finset ℕ), S ∈ Erdos168.IntervalNonTernarySets N ↔ Erdos168.NonTernary S ∧ S ⊆ Finset.Icc 1 NAPIStatement only, no proof