Skip to content

Erdős problem 236

Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k≥0k\geq 0. Show that f(n)=o(log⁡n)f(n)=o(\log n).

Sources

The source's own material, retained exactly.

1 retained statement36c6d0fef71a

Open selected source

FormalConjectures/ErdosProblems/

236.lean

Retained formal statement1 of 1

Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k≥0k\geq 0. Show that f(n)=o(log⁡n)f(n)=o(\log n).

FormalConjectures/ErdosProblems/236.leanErdos236.erdos_2361 lineExact file
(fun n => ↑(Erdos236.f n)) =o[Filter.atTop] fun n => Real.log ↑n
OpenStatement only, no proof