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Erdős problem 236

Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k0k\geq 0. Show that f(n)=o(logn)f(n)=o(\log n).

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FormalConjectures/ErdosProblems/

236.lean

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Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k0k\geq 0. Show that f(n)=o(logn)f(n)=o(\log n).

FormalConjectures/ErdosProblems/236.leanErdos236.erdos_2361 lineExact file
(fun n => ↑(Erdos236.f n)) =o[Filter.atTop] fun n => Real.logn
OpenStatement only, no proof

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