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Erdős problem 283

Let p ⁣:Z→Zp\colon \mathbb{Z} \rightarrow \mathbb{Z} be a polynomial whose leading coefficient is positive and such that there exists no d≥2d≥2 with d∣p(n)d ∣ p(n) for all n≥1n≥1. Is it true that, for all sufficiently large mm, there exist integers 1≤n1<⋯<nk1≤n_1<\dots < n_k such that 1=1n1+⋯+1nk1=\frac{1}{n_1}+\cdots+\frac{1}{n_k} and m=p(n1)+⋯+p(nk)m=p(n_1)+\cdots+p(n_k)?

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FormalConjectures/ErdosProblems/

283.lean

Retained formal statement2 of 8

Alekseyev [Al19] has proved this when p(x)=x2p(x)=x^2, for all m>8542m>8542.

FormalConjectures/ErdosProblems/283.leanErdos283.erdos_283.variants.alekseyev1 lineExact file
∀ m > 8542, ∃ S, (∀ n ∈ S, 1 ≤ n) ∧ ∑ n ∈ S, 1 / ↑n = 1 ∧ ∑ n ∈ S, ↑n ^ 2 = ↑m
SolvedStatement only, no proof