Skip to content

Erdős problem 283

Let p ⁣:ZZp\colon \mathbb{Z} \rightarrow \mathbb{Z} be a polynomial whose leading coefficient is positive and such that there exists no d2d≥2 with dp(n)d ∣ p(n) for all n1n≥1. Is it true that, for all sufficiently large mm, there exist integers 1n1<<nk1≤n_1<\dots < n_k such that 1=1n1++1nk1=\frac{1}{n_1}+\cdots+\frac{1}{n_k} and m=p(n1)++p(nk)m=p(n_1)+\cdots+p(n_k)?

Sources

Browse retained paths and inspect the exact material available for this Problem.

8 retained statements2415f78e850a

Open selected source

FormalConjectures/ErdosProblems/

283.lean

Retained formal statement2 of 8

Alekseyev [Al19] has proved this when p(x)=x2p(x)=x^2, for all m>8542m>8542.

FormalConjectures/ErdosProblems/283.leanErdos283.erdos_283.variants.alekseyev1 lineExact file
m > 8542, ∃ S, (∀ nS, 1 ≤ n) ∧ ∑ nS, 1 / ↑n = 1 ∧ ∑ nS, ↑n ^ 2 = ↑m
SolvedStatement only, no proof

Search problems.science

Find a Problem, Result, source, or page