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Erdős problem 283

Let p ⁣:ZZp\colon \mathbb{Z} \rightarrow \mathbb{Z} be a polynomial whose leading coefficient is positive and such that there exists no d2d≥2 with dp(n)d ∣ p(n) for all n1n≥1. Is it true that, for all sufficiently large mm, there exist integers 1n1<<nk1≤n_1<\dots < n_k such that 1=1n1++1nk1=\frac{1}{n_1}+\cdots+\frac{1}{n_k} and m=p(n1)++p(nk)m=p(n_1)+\cdots+p(n_k)?

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Browse retained paths and inspect the exact material available for this Problem.

8 retained statements2415f78e850a

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FormalConjectures/ErdosProblems/

283.lean

Retained formal statement5 of 8

Graham [Gr63] has proved this when p(x)=xp(x)=x.

FormalConjectures/ErdosProblems/283.leanErdos283.erdos_283.variants.graham1 lineExact file
Erdos283.Condition Polynomial.X
SolvedStatement only, no proof

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