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Erdős problem 353

Let A⊆R2A\subseteq \mathbb{R}^2 be a measurable set with infinite measure. Must AA contain the vertices of an isosceles trapezoid of area 11? What about an isosceles triangle, or a right-angled triangle, or a cyclic quadrilateral, or a convex polygon with congruent sides?

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FormalConjectures/ErdosProblems/

353.lean

Retained formal statement5 of 5

Every measurable A⊆R2A\subseteq \mathbb{R}^2 with infinite measure contains the vertices of a right-angled triangle of area 11.

Koizumi [Ko25] has resolved this question, proving that any set with infinite measure must contain the vertices of an isosceles trapezoid, an isosceles triangle, and a right-angled triangle, all of area 11.

Note the area condition forces a, b, c to be affinely independent, so no separate non-degeneracy hypothesis is needed.

FormalConjectures/ErdosProblems/353.leanErdos353.erdos_353.variants.right_angled_triangle5 linesExact file
∀ (A : Set (EuclideanSpace ℝ (Fin 2))),  MeasurableSet A →    MeasureTheory.volume A = ⊤ →      ∃ a ∈ A,        ∃ b ∈ A, ∃ c ∈ A, EuclideanGeometry.IsRightAngled a b c ∧ MeasureTheory.volume ((convexHull ℝ) {a, b, c}) = 1
SolvedProof has a holelean4external proof

The proof uses `sorry`: part of the argument is written but not proved. Lean accepts the file; it does not accept the theorem.