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Erdős problem 358

When An=nA_n = n, the function ff defined above counts the number of odd divisors of nn.

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FormalConjectures/ErdosProblems/

358.lean

Retained formal statement2 of 6

Let A={a1<}A=\{a_1 < \cdots\} be an infinite sequence of integers. Let f(n)f(n) count the number of solutions to n=uivai.n=\sum_{u\leq i\leq v}a_i. Is there an AA such that f(n)2f(n)\geq 2 for all large nn?

This also follows from Tao's construction with f(n)lognf(n) \gg \log n [Ta26].

FormalConjectures/ErdosProblems/358.leanErdos358.erdos_358.parts.ii1 lineExact file
True ↔ ∃ A, StrictMono A ∧ ∀ᶠ (n : ℕ) in Filter.atTop, 2 ≤ Erdos358.f A n
SolvedStatement only, no proof

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