Erdős problem 36
This example calculates the value of . The set is , so the only partition is (or vice versa). The possible differences are and . The Overlap for is 1 (if ) and for also 1 (if ). The MaxOverlap is , since the Overlap is for other . Thus, .
Sources
FormalConjectures/ErdosProblems/
36.lean
Retained formal statement
For , the set is . The balanced partition has all four pairwise differences () distinct, so MaxOverlap = 1. Any balanced partition has both pieces nonempty, so MaxOverlap \geq 1.
Erdos36.M 2 = 1TestStatement only, no proof