Erdős problem 36
This example calculates the value of . The set is , so the only partition is (or vice versa). The possible differences are and . The Overlap for is 1 (if ) and for also 1 (if ). The MaxOverlap is , since the Overlap is for other . Thus, .
Sources
FormalConjectures/ErdosProblems/
36.lean
Retained formal statement
The limit of MinOverlapQuotient exists and it is less than .
∃ c, Filter.Tendsto Erdos36.MinOverlapQuotient Filter.atTop (nhds c) ∧ c < 0.385694SolvedStatement only, no proof