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Erdős problem 442

Let Logx:=max{logx,1}\operatorname{Log} x := \max\{\log x, 1\}, Log2x=Log(Logx)\operatorname{Log}_2x = \operatorname{Log} (\operatorname{Log} x), and Log3x=Log(Log(Logx)).\operatorname{Log}_3x = \operatorname{Log}(\operatorname{Log}(\operatorname{Log} x)). Is it true that if ANA\subseteq\mathbb{N} is such that 1Log2xnA:nx1n \frac{1}{\operatorname{Log}_2 x} \sum_{n\in A: n\leq x} \frac{1}{n}\to\infty then (nA:nx1n)2n,mA:n<mx1lcm(n,m) \left(\sum_{n\in A: n\leq x} \frac{1}{n}\right)^2 \sum_{n, m \in A: n < m \leq x} \frac{1}{\operatorname{lcm}(n, m)}\to\infty as xx\to\infty?

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FormalConjectures/ErdosProblems/

442.lean

Retained formal statement2 of 2

Tao resolved erdos_442 in the negative in Theorem 1 of https://arxiv.org/pdf/2407.04226. The following is a formalisation of that theorem with C0=1C_0 = 1.

Let Logx:=max{logx,1}\operatorname{Log} x := \max\{\log x, 1\}, Log2x=Log(Logx)\operatorname{Log}_2x = \operatorname{Log} (\operatorname{Log} x), and Log3x=Log(Log(Logx)).\operatorname{Log}_3x = \operatorname{Log}(\operatorname{Log}(\operatorname{Log} x)). There exists a set AA of natural numbers such that nA:nx1n=exp(((12+o(1))Log21/2xLog3x)) \sum_{n\in A: n\leq x} \frac{1}{n} = \exp\left(\left(\left(\frac{1}{2} + o(1)\right)\operatorname{Log}_2^{1/2}x \operatorname{Log}_3x\right)\right) and n,mA:n,mx1lcm(n,m)(nA:nx1n)2 \sum_{n, m\in A: n, m\leq x} \frac{1}{\operatorname{lcm}(n, m)}\ll\left(\sum_{n\in A: n\leq x} \frac{1}{n}\right)^2

FormalConjectures/ErdosProblems/442.leanErdos442.erdos_442.variants.tao9 linesExact file
A f C,  ∃ (_ : 0 < C) (_ : f =o[Filter.atTop] 1),    ∀ᶠ (x : ℝ) in Filter.atTop,n ∈ (ASet.Icc 1 ⌊x⌋₊).toFinset, 1 / ↑n =          Real.exp            ((1 / 2 + f x) * √(Erdos442.Real.maxLogOne (Erdos442.Real.maxLogOne x)) *              Erdos442.Real.maxLogOne (Erdos442.Real.maxLogOne (Erdos442.Real.maxLogOne x))) ∧        |∑ nm ∈ ((ASet.Icc 1 ⌊x⌋₊) ×ˢ (ASet.Icc 1 ⌊x⌋₊)).toFinset, 1 / ↑(nm.1.lcm nm.2)| ≤          C * (∑ n ∈ (ASet.Icc 1 ⌊x⌋₊).toFinset, 1 / ↑n) ^ 2
SolvedStatement only, no proof

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