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Erdős problem 494

Selfridge and Straus [SeSt58] also showed that the conjecture is true when 1) k=3k = 3 and ∣A∣>6|A| > 6 or 2) k=4k = 4 and ∣A∣>12|A| > 12. More generally, they proved that AA is determined by AkA_k (and ∣A∣|A|) if ∣A∣|A| is divisible by a prime greater than kk.

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FormalConjectures/ErdosProblems/

494.lean

Retained formal statement2 of 9

Similarly, Tao noted that the conjecture fails when ∣A∣=2k|A| = 2k, by taking AA to be a set of the total sum 0 and considering −A-A.

FormalConjectures/ErdosProblems/494.leanErdos494.erdos_494.variants.card_eq_2k1 lineExact file
∀ k > 2, ¬Erdos494.Erdos494Unique k (2 * k)
SolvedStatement only, no proof