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Erdős problem 494

Selfridge and Straus [SeSt58] also showed that the conjecture is true when 1) k=3k = 3 and ∣A∣>6|A| > 6 or 2) k=4k = 4 and ∣A∣>12|A| > 12. More generally, they proved that AA is determined by AkA_k (and ∣A∣|A|) if ∣A∣|A| is divisible by a prime greater than kk.

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FormalConjectures/ErdosProblems/

494.lean

Retained formal statement5 of 9

Selfridge and Straus [SeSt58] gave counterexamples to the conjecture when k=2k = 2 and ∣A∣=2l|A| = 2^l.

FormalConjectures/ErdosProblems/494.leanErdos494.erdos_494.variants.k_eq_2_card_pow_two1 lineExact file
∀ (card : ℕ), (∃ l, card = 2 ^ l) → ¬Erdos494.Erdos494Unique 2 card
SolvedStatement only, no proof