Each move claims exactly one pool element, so the minimax value never exceeds the number of already claimed elements plus the number of still unclaimed elements.

Erdős Problem 872, part (ii) (strong form): for every $\epsilon > 0$, the game length is at least $(1-\epsilon) \cdot n / 2$ for all sufficiently large $n$.

Status note: the forum thread (April-May 2026) records Shortener strategies giving $L(n) \leq (23/48 + o(1)) \cdot n$ (described in the thread as accepted as correct, with a Lean formalization in progress) and a claimed $L(n) \leq 0.19 \cdot n$, either of which would answer this question negatively under the Prolonger-first convention. Neither is published, so the statement is recorded here as the original Erdős question.