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Erdős Problems

1,217 source-owned questions · 604 with a formal statement · searchable by statement, number, topic and source status.

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Collection coverage

Source status, exact formal material, and reviewed Results are separate signals.

  • Open per source608
  • Resolved per source556
  • Other source status53
Exact formal statement available604 / 1,217
With Repository-reviewed evidence2 / 1,217
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Problems

61 Problems

2/2

NumberQuestionOpen
#1059Are there infinitely many primes pp such that pk!p - k! is composite for each kk such that 1k!<p1 ≤ k! < p?openFormalized
#1137Let dn=pn+1pnd_n=p_{n+1}-p_n, where pnp_n denotes the nnth prime. Is it true that maxn<xdndn1(maxn<xdn)20\frac{\max_{n < x}d_{n}d_{n-1}}{(\max_{n < x}d_n)^2}\to 0 as xx\to \infty?openFormalized
#1138Erdős Problem 1138. Let x/2<y<xx/2 < y < x and C>1C > 1. If d=maxpn<x(pn+1pn)d = \max_{p_n < x}(p_{n+1} - p_n), where pnp_n denotes the nn-th prime, then is it true that π(y+Cd)π(y)Cdlogy\pi(y + Cd) - \pi(y) \sim \frac{Cd}{\log y}?disproved (Lean)Formalized
#1139Let 1u1<u2<1\leq u_1 < u_2 < \cdots be the sequence of integers with at most 22 prime factors. Is it true that lim supkuk+1uklogk=?\limsup_{k \to \infty} \frac{u_{k+1}-u_k}{\log k}=\infty?openFormalized
#1141Are there infinitely many nn such that nk2n-k^2 is prime for all kk with (n,k)=1(n,k)=1 and k2<nk^2 < n?disproved (Lean)Formalized
#1142Are there infinitely many n>2n > 2 such that n2kn - 2^k is prime for all k1k \geq 1 with 2k<n2^k < n?openFormalized
#1143No statement retained — open to read what the source holdsopenNo formal declaration
#1184No statement retained — open to read what the source holdsopenNo formal declaration
#1187No statement retained — open to read what the source holdssolvedNo formal declaration
#1200No statement retained — open to read what the source holdsopenNo formal declaration
#1201Is it true that for every ϵ,η>0\epsilon,\eta>0 there exists a kk such that the density of nn for which P(n(n+1)(n+k))>n1ϵP(n(n+1)\cdots(n+k))>n^{1-\epsilon} is at least 1η1-\eta (where P(m)P(m) is the greatest prime divisor of mm)?openFormalized
#1202No statement retained — open to read what the source holdssolvedNo formal declaration
#1212Roughness criterion (sufficiency for the anchor conditions): if a<sa < s for all ss in the leg and the leg stays below a+P(a)a + P^-(a), then aa is coprime to the whole leg. Stated via divisibility: no prime factor of aa divides any ss with a<s<a+pa < s < a + p for all prime factors pp of aa.openFormalized

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