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Problem

erdos:45

True ↔ ∀ (k : ℕ), 2 ≤ k → ∃ n, ∀ (colouring : ℕ → Fin k), ∃ colour, ∃ D' ⊆ {d ∈ n.divisors | 1 < d ∧ d < n}, (∀ d ∈ D', colouring d = colour) ∧ D'.reciprocalSum = 1

Declared status
proved (Lean)
Formalization
formalized
OEIS
possible

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