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Erdős problem 377

Is there some absolute constant C>0C > 0 such that ∑p≤n1p∤(2nn)1p≤C \sum_{p \leq n} 1_{p\nmid {2n \choose n}}\frac{1}{p} \leq C for all nn?

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5 retained statements36c6d0fef71a

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FormalConjectures/ErdosProblems/

377.lean

Retained formal statement1 of 5

Is there some absolute constant C>0C > 0 such that ∑p≤n1p∤(2nn)1p≤C \sum_{p \leq n} 1_{p\nmid {2n \choose n}}\frac{1}{p} \leq C for all nn?

FormalConjectures/ErdosProblems/377.leanErdos377.erdos_3771 lineExact file
True ↔ ∃ C > 0, ∀ (n : ℕ), Erdos377.sumInvPrimesNotDvdCentralBinom n ≤ C
OpenStatement only, no proof