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Erdős problem 618

For a triangle-free graph GG let h2(G)h_2(G) be the smallest number of edges that need to be added to GG so that it has diameter 22 and is still triangle-free. Is it true that if GG has maximum degree o(n1/2)o(n^{1/2}) then h(G)=o(n2)h(G)=o(n^2)?

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FormalConjectures/ErdosProblems/

618.lean

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For a triangle-free graph GG let h2(G)h_2(G) be the smallest number of edges that need to be added to GG so that it has diameter 22 and is still triangle-free. Is it true that if GG has maximum degree o(n1/2)o(n^{1/2}) then h(G)=o(n2)h(G)=o(n^2)?

A problem of Erdős, Gyárfás, and Ruszinkó [EGR98]. Simonovits showed that there exist graphs GG with maximum degree n1/2\gg n^{1/2} and h2(G)n2h_2(G)\gg n^2. Alon has observed this problem is essentially identical to [134], and his solution in [this note](https://web.math.princeton.edu/~nalon/PDFS/remark1901.pdf) also solves this problem in the affirmative.

FormalConjectures/ErdosProblems/618.leanErdos618.erdos_6185 linesExact file
True  ∀ (G : (n : ℕ) → SimpleGraph (Fin n)),    (∀ (n : ℕ), (G n).CliqueFree 3) →      ((fun n => ↑(G n).maxDegree) =o[Filter.atTop] fun n => ↑n ^ (1 / 2)) →        (fun n => ↑(Erdos618.h2 (G n))) =o[Filter.atTop] fun n => ↑n ^ 2
SolvedProof has a holelean4external proof

The proof uses `sorry`: part of the argument is written but not proved. Lean accepts the file; it does not accept the theorem.

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