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Problem

erdos:785

True ↔ ∀ (A B : Set ℕ), A.Infinite → B.Infinite → Erdos785.IsExactAdditiveComplement A B → Filter.Tendsto (fun x => ↑(Erdos785.counting A x) * ↑(Erdos785.counting B x) - ↑x) Filter.atTop Filter.atTop

Declared status
proved (Lean)
Formalization
formalized
OEIS
N/A

exact additive complements

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